Quadratic Formula Word Problems Answers
ters, find the dimensions. **Solution:** Let the width be \(x\), then length is \(x + 3\). The area \(A = length \times width\): \[ x(x + 3) = 70 \] \[ x^2 + 3x - 70 = 0 \] Here, \(a = 1\), \(b = 3\), and \(c = -70\). Discrim