acid base titration lab 13c answers
e reaction is 1:1, the mass of pure acid is: \[ \text{Mass} = \text{moles} \times M_{acid} \] Without the molar mass, we focus on the ratio: If the molar mass is known, say \(M_{acid}\), then: \[ \text{Mass of pure acid} = 0.00200\, \text{mol} \times M_{acid} \] Percent purity